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Thursday, April 5, 2012

n元不等式:
n∈N


证:令


  知
f(n)是增函数
所以在n取1时有最小值1/2.


Thursday, March 15, 2012

高考不等式

Let a,b,c≥0 a+b+c=3
show that
 

Saturday, March 10, 2012

Another proof of APMO inequality

Aassila's inequality

a,b,c are positive reals
show that:

APMO inequality

If a,b,c>0 show that (a²+2)(b²+2)(c²+2)≥9(ab+bc+ca)

Prove: Let          
we just need to show that



in fact we can easily got:








Now the original inequality is equivalent to
2(xy+yz+zx)-2(xy²+yz²+zx²)-2(x²y+y²z+z²x)≤2/9 
xy²+yz²+zx²+x²y+y²z+z²x+1/9≥xy+yz+zx


by AM-GM we obtain:


                                                           

                                                                                                              Q.E.D

Friday, March 9, 2012

Triangle inequality

Let  then we have:

  Prove:


We can use make this geometry graph

Let AiBi+1=ai

CiCi+1=bi

by Pythagoras's theorem we have:





because the shortest distance of two point is a line segment

we obviously have:

       
the equality holds if and only if                                                 Q.E.D

Let a,b,c be the positive reals
Show that



we can apply triangle inequality:


The inequality is now equivalent to

 where x=a+b+c,but this is the easy exercise of quadratic function.

Tuesday, March 6, 2012

Let ABCD be a quadrilateral E,F,G,H be the middle points of AB BC CD DA

Prove that

Monday, March 5, 2012

some Geometric inequalities


Let a,b,c be the lengths of a triangle R be the radius of the circumcircle
p=a+b+c s=(a+b+c)/2
there we have:









Saturday, March 3, 2012

A tip.

In order to prove ∑F(x,y,z)>=C,we can consider that to prove

F(x,y,z)>=G(x,y,z) where ∑G(x,y,z)=C

inequality

Let a,c,b>0 a+b+c=2

prove:

Thursday, March 1, 2012

combinatorial identities

Let n be a positive integer, then

(1)
(2)

Prove of (1):Let



Notice that:

So
we can select k(k<=n) a_is from Set A and select n-k b_is things from Set B
So we have ways

but it is equivalent to select n a_i s or b_i s from Set S because |S|=2n
So we obtain the rusult.

Prove of (2):

by the same property of Combinatorial number
we have:
 
So

Wednesday, February 22, 2012

if x,y are real number


Prove:

Let

then we obtain:


since
So pq=1 put it into x and y we obtain the identity

Monday, February 13, 2012

This is a place that might be able to help:  http://swanservices.org/

I will email them for more information

Saturday, February 4, 2012

AM-GM

Well.I think I learn how to use AM-GM skillfully now.

Wednesday, February 1, 2012

Grade B

I got B during the Civics Test. I think if I worked hard I would get brtter grade...